Answer
See the explanation
Work Step by Step
The mistake is $4$ is substituted for $x$ instead of $y$. $4$ is the value of $y$ not $x$.
Fix the error:
$$4=3x^2-6x+4$$
$$3x^2-6x=0$$
$$3x(x-2)=0$$
$$x=0~~~or~~~x=2$$
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 9 - Solving Quadratic Equations - 9.6 - Solving Nonlinear Systems of Equations - Exercises - Page 531: 28
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