Answer
The graph of $y=x^2-x$ has two $x-$intercepts.
Work Step by Step
The given function is
$\Rightarrow y=x^2-x$
Find the number of real solutions of $0=x^2-x$
$= b^2-4ac$
Substitute $1$ for $a,-1$ for $b,$ and $0$ for $c$.
$= (-1)^2-4(1)(0)$
Simplify.
$= 1-0$
Subtract.
$= 1$
Discriminant is greater than $0$,
Hence, the equation has two real solutions.
The graph of $y=x^2-x$ has two $x-$intercepts.
