Answer
The equation has no real solution.
Work Step by Step
$6x^{2}+2x=-1\implies6x^{2}+2x+1=0 $
Comparing $6x^{2}+2x+1=0$ with $ax^{2}+bx+c$, we see that
$a=6, b=2$ and $c=1$.
$b^{2}-4ac=(2)^{2}-4(6)(1)=-20$.
The discriminant is negative. So, the equation has no real solution.
