Answer
$x=\frac{-1+\sqrt {22}}{-3}\approx-1.2$ and $x= \frac{-1-\sqrt {22}}{-3}\approx1.9$
Work Step by Step
$-3x^{2}+2x+7=0$
Comparing $-3x^{2}+2x+7=0$ with $ax^{2}+bx+c=0$, we get
$a=-3$, $b=2$ and $c=7$.
The quadratic formula is
$x=\frac{-b \pm \sqrt {b^{2}-4ac}}{2a}$
Substituting the values, we get
$x=\frac{-(2) \pm \sqrt {(2)^{2}-4(-3)(7)}}{(2)(-3)}=\frac{-2\pm \sqrt {88}}{-6}$
The solutions of the equation are $x=\frac{-1+\sqrt {22}}{-3}\approx-1.2$ and $x= \frac{-1-\sqrt {22}}{-3}\approx1.9$
