Answer
$x=\frac{5}{2}$ or $x=-\frac{7}{2}$
Work Step by Step
The given equation is
$\Rightarrow (2x+1)^2=36$
Take the square root of each side.
$\Rightarrow 2x+1=\pm6$
Subtract $1$ from each side.
$\Rightarrow 2x+1-1=-1\pm6$
Simplify.
$\Rightarrow 2x=-1\pm6$
Divide each side by $2$.
$\Rightarrow x=\frac{-1\pm6}{2}$
Two real solutions are
$\Rightarrow x=\frac{-1+6}{2}$ or $x=\frac{-1-6}{2}$
Simplify.
$\Rightarrow x=\frac{5}{2}$ or $x=-\frac{7}{2}$
Hence, the solutions are $x=\frac{5}{2}$ or $x=-\frac{7}{2}$.
