Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Monitoring Progress - Page 480: 2

Answer

$-4\sqrt{5}$.

Work Step by Step

The given expression is $=-\sqrt{80}$ Factor as square terms. $=-\sqrt{16\cdot 5}$ Use product property of square roots. $=-\sqrt{16}\cdot \sqrt{5}$ Use $16=4^2$. $=-\sqrt{4^2}\cdot \sqrt{5}$ Simplify. $=-4\sqrt{5}$.
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