Answer
$2$
Work Step by Step
The given function is
$\Rightarrow g(x)=3x^2-12x+12$
Substitute $0$ for $g(x)$.
$\Rightarrow 0=3x^2-12x+12$
Factor out $3$.
$\Rightarrow 0=3(x^2-4x+4)$
Factor the trinomial.
$\Rightarrow 0=3(x-2)(x-2)$
Use zero product property.
$\Rightarrow x-2=0$ or $x-2=0$
Solve for $x$.
$\Rightarrow x=2$ or $x=2$
Hence, the zero of the function is $2$.
