Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 7 - Polynomial Equations and Factoring - 7.8 - Factoring Polynomials Completely - Monitoring Progress - Page 405: 3

Answer

$3x(x+2)(x-2)$.

Work Step by Step

The given polynomial is $= 3x^3-12x$ Factor out $3x$. $= 3x(x^2-4)$ Write the the polynomial as $a^2-b^2$. $= 3x(x^2-2^2)$ Use difference of two square pattern $a^2-b^2=(a+b)(a-b)$. We have $a=x$ and $b=2$. $= 3x(x+2)(x-2)$ Hence, the complete factor of the polynomial is $3x(x+2)(x-2)$.
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