Answer
$s=0$ and $s=3$.
Work Step by Step
The given equation is
$\Rightarrow 3s^2-9s=0$
Factor out $3s$.
$\Rightarrow 3s(s-3)=0$
Use zero-product property rule.
$\Rightarrow 3s=0$ or $s-3=0$
Solve for $s$.
$\Rightarrow s=0$ or $s=3$
Check:-
$s=0$
$\Rightarrow 3(0)^2-9(0)=0$
$\Rightarrow 0-0=0$
$\Rightarrow 0=0$
True.
Check:-
$s=3$
$\Rightarrow 3(3)^2-9(3)=0$
$\Rightarrow 3(9)-27=0$
$\Rightarrow 27-27=0$
$\Rightarrow 0=0$
True.
Hence, the solutions are $s=0$ and $s=3$.
