Answer
$z^2+4z-12$.
Work Step by Step
The given expression is
$=(z-2)(z+6)$
Distribute $(z+6)$ to each term of $(z-2)$.
$=z(z+6)-2(z+6)$
Use distributive property.
$=z(z)+z(6)-2(z)-2(6)$
Multiply.
$=z^2+6z-2z-12$
Combine like terms.
$=z^2+4z-12$
Hence, the product is $z^2+4z-12$.
