Answer
$\frac{1}{3^{3}z^{18}}$.
Work Step by Step
The given expression is
$=(3z^6)^{-3}$
Use properties of exponents $(ab)^n=a^n\cdot b^n$.
$=(3)^{-3}(z^6)^{-3}$
Use properties of exponents $(a^n)^m=a^{n\cdot m}$.
$=3^{-3}z^{6\cdot (-3)}$
Simplify.
$=3^{-3}z^{-18}$
Use properties of exponents $a^{-n}=\frac{1}{a^{n}}$.
$=\frac{1}{3^{3}z^{18}}$.
