Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 6 - Exponential Functions and Sequences - Chapter Review - Page 348: 4

Answer

$\frac{25y^{8}}{4x^{4}}$

Work Step by Step

The given expression is $=(\frac{2x^2}{5y^4})^{-2}$ Use $(\frac{a}{b})^n=\frac{a^n}{b^n}$. $=\frac{(2x^2)^{-2}}{(5y^4)^{-2}}$ Use $(ab)^m=a^{m}\cdot b^{m}$. $=\frac{(2)^{-2}(x^2)^{-2}}{(5)^{-2}(y^4)^{-2}}$ Use $(a^m)^n=a^{m\cdot n}$. $=\frac{2^{-2}x^{2(-2)}}{5^{-2}y^{4(-2)}}$ Simplify. $=\frac{2^{-2}x^{-4}}{5^{-2}y^{-8}}$ Use $a^{-n}=\frac{1}{a^n}$. $=\frac{5^{2}y^{8}}{2^{2}x^{4}}$ Simplify. $=\frac{25y^{8}}{4x^{4}}$
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