Answer
A recursive rule for the sequence is
$a_1=-14,a_n=a_{n-1}+6$
Work Step by Step
The given explicit rule is
$a_n=6n-20$
First term is
$a_1=6-20=-14$
Common difference is
$d=6$
Recursive equation for an arithmetic sequence.
$a_n=a_{n-1}+d$
Substitute $6$ for $d$.
$a_n=a_{n-1}+6$
Hence, a recursive rule for the sequence is
$a_1=-14,a_n=a_{n-1}+6$
