Answer
59049
Work Step by Step
$a_{n}=a_{1}r^{n-1}$
$a_{3}=a_{1}r^{3-1}=a_{1}r^{2}=a_{1}\cdot 3^{2}=81$
$\implies a_{1}=\frac{81}{3^{2}}=9$
$a_{9}=a_{1}r^{9-1}=9\cdot 3^{8}=59049$
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