Answer
$ y=3500(1.023)^{4t}$
Work Step by Step
The given values are
Initial amount $P=\$3500$.
Rate of interest $r=9.2\%=0.092$.
Number of time interest is compounded per year.
$n=4
$.
Formula for the compound interest
$\Rightarrow y=P(1+\frac{r}{n})^{nt}$
Substitute all the values.
$\Rightarrow y=3500(1+\frac{0.092}{4})^{4t}$
Simplify.
$\Rightarrow y=3500(1+0.023)^{4t}$
$\Rightarrow y=3500(1.023)^{4t}$.
