Answer
$-4$
Work Step by Step
$$\begin{align*}
\displaystyle \frac{-5^{0}}{2^{-2}}& =\displaystyle \frac{-(\boxed{5^{0}})}{2^{-2}} \\
&\small\text{For any nonzero number $a$, the number $a^{0}=1$.} \\
&=\displaystyle \frac{-1}{2^{-2}} \\
&\small\text{For any integer $n$ and any nonzero number $a$, the number $a^{-n}$ is the reciprocal of $a^{n}$.} \\
&=\displaystyle \frac{-1}{\left (\frac{1}{2^{2}}\right)} \\
&=\displaystyle \frac{-1}{\frac{1}{4}}\\
&=-1\displaystyle \div\frac{1}{4} \\
&=-1\displaystyle \times\frac{4}{1} \\
&=-4 \end{align*}$$