Answer
The system of linear equations has no solution.
Work Step by Step
The given system of equations is
$x=y+2$ ...... (1)
$-3x+3y=6$ ...... (2)
Multiply equation (1) by $3$.
$3x=3(y+2)$
Use distributive property.
$3x=3y+6$ ...... (3)
Add equation (2) and (3).
$\Rightarrow -3x+3y+3x=6+3y+6$
Add like terms.
$\Rightarrow 3y=3y+12$
Subtract $3y$ from each side.
$\Rightarrow 3y-3y=3y+12-3y$
Simplify.
$\Rightarrow 0=12$
The equation $0=12$ is never true.
Hence, the system of linear equations has no solution.
