Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - Chapter Review - Page 282: 4

Answer

The solution is $(-2,-3)$.

Work Step by Step

The given system of equations is $\Rightarrow 3x+y=-9$ ...... (1) $\Rightarrow y=5x+7$ ...... (2) Substitute $5x+7$ for $y$ in equation (1). $\Rightarrow 3x+5x+7=-9$ Add like terms. $\Rightarrow 8x+7=-9$ Subtract $7$ from each side. $\Rightarrow 8x+7-7=-9-7$ Simplify. $\Rightarrow 8x=-16$ Divide each side by $8$. $\Rightarrow \frac{8x}{8}=-\frac{16}{8}$ Simplify. $\Rightarrow x=-2$ Substitute $-2$ for $x$ in equation (2). $\Rightarrow y=5(-2)+7$ Simplify. $\Rightarrow y=-10+7$ $\Rightarrow y=-3$ Check $(x,y)=(-2,-3)$ Equation (1) $\Rightarrow 3x+y=-9$ $\Rightarrow 3(-2)-3=-9$ $\Rightarrow -6-3=-9$ $\Rightarrow -9=-9$ True. Equation (2) $\Rightarrow y=5x+7$ $\Rightarrow -3=5(-2)+7$ $\Rightarrow -3=-10+7$ $\Rightarrow -3=-3$ True. Hence, the solution is $(-2,-3)$.
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