Answer
The system of linear equations has no solution.
Work Step by Step
The given system of equations is
$y=-10x+2$ ...... (1)
$10x+y=10$ ...... (2)
Multiply equation (1) by $-1$.
$-1(y)=-1(-10x+2)$
Use distributive property.
$-y=10x-2$ ...... (3)
Add equation (2) and (3).
$\Rightarrow 10x+y-y=10+10x-2$
Add like terms.
$\Rightarrow 10x=8+10x$
Subtract $10x$ from each side.
$\Rightarrow 10x-10x=8+10x-10x$
Simplify.
$\Rightarrow 0=8$
The equation $0=8$ is never true.
Hence, the system of linear equations has no solution.
