Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.4 - Solving Special Systems of Linear Equations - Exercises - Page 257: 10

Answer

The system of linear equations has no solution.

Work Step by Step

The given system of equations is $y=-6x-8$ ...... (1) $y=-6x+8$ ...... (2) Multiply equation (1) by $-1$. $\Rightarrow -1(y)=-1(-6x-8)$ Use distributive property. $\Rightarrow -y=6x+8$ ...... (3) Add equation (2) and (3). $\Rightarrow y-y=-6x+8+6x+8$ Add like terms. $\Rightarrow 0=16$ The equation $0=16$ is never true. Hence, the system of linear equations has no solution.
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