Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 5 - Solving Systems of Linear Equations - 5.2 - Solving Systems of Linear Equations by Substitution - Monitoring Progress - Page 243: 4

Answer

$(-2,0)$

Work Step by Step

The given system of equations is $\Rightarrow x+y=-2$ ...... (1) $\Rightarrow -3x+y=6$ ...... (2) Solve for $y$ in equation (2). $\Rightarrow y=6+3x$ ...... (3) Substitute $6+3x$ for $y$ in equation (1). $\Rightarrow x+6+3x=-2$ Add like terms. $\Rightarrow 6+4x=-2$ Subtract $6$ from each side. $\Rightarrow 6+4x-6=-2-6$ Simplify. $\Rightarrow 4x=-8$ Divide each side by $4$. $\Rightarrow \frac{4x}{4}=\frac{-8}{4}$ Simplify. $\Rightarrow x=-2$ Substitute $-2$ for $x$ in equation (3). $\Rightarrow y=6+3(-2)$ Simplify. $\Rightarrow y=6-6$ $\Rightarrow y=0$ Check Equation (1) $\Rightarrow x+y=-2$ $\Rightarrow -2+0=-2$ $\Rightarrow -2=-2$ True. Check Equation (2) $\Rightarrow -3(-2)+0=6$ $\Rightarrow -6+0=6$ $\Rightarrow -6=-6$ True. Hence, the solution is $(-2,0)$.
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