Answer
$(-4,1)$
Work Step by Step
The given system of linear equation is
$y=\frac{1}{2}x+3$ ...... (1)
$y=-\frac{3}{2}x-5$ ...... (2)
Graph each equation.
The intersection point is $(-4,1)$.
Check the intersection point.
Equation 1:
$\Rightarrow y=\frac{1}{2}x+3$
$\Rightarrow 1=\frac{1}{2}(-4)+3$
$\Rightarrow 1=-2+3$
$\Rightarrow 1=1$
True.
Equation 2:
$\Rightarrow y=-\frac{3}{2}x-5$
$\Rightarrow 1=-\frac{3}{2}(-4)-5$
$\Rightarrow 1=6-5$
$\Rightarrow 1=1$
True.
The solution is $(-4,1)$.
