Answer
$y-2=-\frac{1}{3}(x+3)$
Work Step by Step
Let $(x_1,y_1)=(-3,2)$ and $(x_2,y_2)=(6,-1)$.
Slope
$\Rightarrow m =\frac{y_2-y_1}{x_2-x_1}$
Substitute all the values.
$\Rightarrow m =\frac{-1-2}{6-(-3)}$
Simplify.
$\Rightarrow m =\frac{-1-2}{6+3}$
$\Rightarrow m =-\frac{3}{9}$
$\Rightarrow m =-\frac{1}{3}$
The point-slope form.
$\Rightarrow y-y_1=m(x-x_1)$
Substitute all the values.
$\Rightarrow y-2=-\frac{1}{3}(x-(-3))$
Simplify.
$\Rightarrow y-2=-\frac{1}{3}(x+3)$
