Answer
The value of $x_1$ is wrong.
The correct equation of the line is
$y-2=\frac{1}{3}(x-1)$
Work Step by Step
The given points are
$(x_1,y_1)=(1,2)$ and $(x_2,y_2)=(4,3)$
Slope
$m=\frac{y_2-y_1}{x_2-x_1}$
Substitute all values.
$m=\frac{3-2}{4-1}$
Simplify.
$m=\frac{1}{3}$.
The point-slope form is
$\Rightarrow y-y_1=m(x-x_1)$
Substitute $\frac{1}{3}$ for $m,1$ for $x_1$ and $2$ for $y_1$.
$\Rightarrow y-2=\frac{1}{3}(x-1)$
Hence, the value of $x_1$ is wrong.
The correct equation of the line is
$y-2=\frac{1}{3}(x-1)$