Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 3 - Graphing Linear Functions - 3.4 - Graphing Linear Equations in Standard Form - Exercises - Page 134: 29

Answer

Hence, the correct graph is $A.$

Work Step by Step

The given linear equation is $\Rightarrow 5x+3y=30$ $x$ intercept. Substitute $0$ for $y$. $\Rightarrow 5x+3(0)=30$ Simplify. $\Rightarrow 5x=30$ Divide each side by $5$. $\Rightarrow \frac{5x}{5}=\frac{30}{5}$ Simplify. $\Rightarrow x=6$ The $x-$ intercept is $6$, so plot the point $A=(6,0)$ $y$ intercept. Substitute $0$ for $x$. $\Rightarrow 5(0)+3y=30$ Simplify. $\Rightarrow 0+3y=30$ $\Rightarrow 3y=30$ Divide each side by $3$. $\Rightarrow \frac{3y}{3}=\frac{30}{3}$ Simplify. $\Rightarrow y=10$ The $y-$ intercept is $10$, so plot the point $B=(0,10)$ Draw a line through the points $A$ and $B$. Hence, the correct graph is $A.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.