Answer
$v(-2)=11$
$v(0)=7$
$v(5)=-3$
Work Step by Step
$v(x)=12-2x-5$
When $x=-2$,
$v(-2)=12-2(-2)-5$
$=12-(-4)-5$
$=11$
$v(0)=12-2(0)-5=7$
$v(5)=12-2(5)-5$
$=12-10-5=-3$
Big Ideas Math - Algebra 1, A Common Core Curriculum
by Larson, Ron; Boswell, Laurie
Published by
Big Ideas Learning LLC
ISBN 10:
978-1-60840-838-2
ISBN 13:
978-1-60840-838-2
Chapter 3 - Graphing Linear Functions - 3.3 - Function Notation - Exercises - Page 125: 9
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