Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - Chapter Test - Page 97: 8

Answer

$2\geq a\geq -3$ The graph is shown below.

Work Step by Step

The given inequality is $\Rightarrow -2\leq 4-3a \leq 13$ Subtract $4$ from each expression. $\Rightarrow -2-4\leq 4-3a-4\leq 13-4$ Simplify. $\Rightarrow -6\leq -3a\leq 9$ Divide each expression by $-3$. Reverse the inequality symbol. $\Rightarrow \frac{-6}{-3}\geq \frac{-3a}{-3}\geq \frac{9}{-3}$ Simplify. $\Rightarrow 2\geq a\geq -3$ Hence, the solution is $2\geq a\geq -3$.
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