Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - 2.5 - Solving Compound Inequalities - Exercises - Page 86: 37

Answer

The solutions are $r=3$ and $r=\frac{1}{2}$. The graph is shown below.

Work Step by Step

The given equation is $\Rightarrow |r+2|=|3r-4|$ Write the two related linear equations. $r+2=3r-4$ ...... (1) $r+2=-(3r-4)$ ...... (2) Solve equation (1). $\Rightarrow r+2=3r-4$ Add $4-r$ to each side. $\Rightarrow r+2+4-r=3r-4+4-r$ Simplify. $\Rightarrow 6=2r$ Divide each side by $2$. $\Rightarrow \frac{6}{2}=\frac{2r}{2}$ Simplify. $\Rightarrow 3=r$ Solve equation (2). $\Rightarrow r+2=-(3r-4)$ Use distributive property. $\Rightarrow r+2=-3r+4$ Add $3r-2$ to each side. $\Rightarrow r+2+3r-2=-3r+4+3r-2$ Simplify. $\Rightarrow 4r=2$ Divide each side by $4$. $\Rightarrow \frac{4r}{4}=\frac{2}{4}$ Simplify. $\Rightarrow r=\frac{1}{2}$ Hence, the solutions are $r=3$ and $r=\frac{1}{2}$.
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