Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - 2.5 - Solving Compound Inequalities - Exercises - Page 85: 20

Answer

$b\lt-3 $ or $b\geq 5$ The graph is shown below.

Work Step by Step

The given inequality is $\Rightarrow 35\lt 7(2-b)$ or $\frac{1}{3}(15b-12) \geq 21$ Solve the first inequality. $\Rightarrow 35\lt 7(2-b)$ Clear the parentheses. $\Rightarrow 35\lt 14-7b$ Add $7b-35$ to each side. $\Rightarrow 35+7b-35\lt 14-7b+7b-35$ Simplify. $\Rightarrow 7b\lt -21$ Divide each side by $7$. $\Rightarrow \frac{7b}{7}\lt \frac{-21}{7}$ Simplify. $\Rightarrow b\lt -3$ Solve the second inequality. $\Rightarrow \frac{1}{3}(15b-12) \geq 21$ Clear the parentheses. $\Rightarrow 5b-4 \geq 21$ Add $4$ to each side. $\Rightarrow 5b-4+4 \geq 21+4$ Simplify. $\Rightarrow 5b \geq 25$ Divide each side by $5$. $\Rightarrow \frac{5b}{5}\geq \frac{25}{5}$ Simplify. $\Rightarrow b\geq 5$ Hence, the solution is $b\lt-3 $ or $b\geq 5$.
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