Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - 2.4 - Solving Multi-Step Inequalities - Monitoring Progress - Page 75: 6

Answer

All real numbers are solutions.

Work Step by Step

The given inequality is $\Rightarrow 2(k-5)\lt 2k+5$ Use distributive property. $\Rightarrow 2k-10\lt 2k+5$ Add $10$ to each side. $\Rightarrow 2k-10+10\lt 2k+5+10$ Simplify. $\Rightarrow 2k\lt 2k+15$ Subtract $2k$ from each side. $\Rightarrow 2k-2k\lt 2k+15-2k$ Simplify. $\Rightarrow 0\lt 15$ The inequality is true. Hence, all real numbers are solutions.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.