Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 2 - Solving Linear Inequalities - 2.3 - Solving Inequalities Using Multiplication or Division - Exercises - Page 72: 43

Answer

$z=6$.

Work Step by Step

The given equation is $\Rightarrow \frac{1}{2}z+4=\frac{5}{2}z-8$ Add $8-\frac{1}{2}z$ to each side. $\Rightarrow \frac{1}{2}z+4+8-\frac{1}{2}z=\frac{5}{2}z-8+8-\frac{1}{2}z$ Simplify. $\Rightarrow 12=\frac{5-1}{2}z$ $\Rightarrow 12=\frac{4}{2}z$ $\Rightarrow 12=2z$ Divide each side by $2$. $\Rightarrow \frac{12}{2}=\frac{2z}{2}$ Simplify. $\Rightarrow 6=z$. Check:- $z=6$ $\Rightarrow \frac{1}{2}(6)+4=\frac{5}{2}(6)-8$ $\Rightarrow 3+4=15-8$ $\Rightarrow 7=7$ True. Hence, the solution is $z=6$.
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