Answer
$f^{-1}(x)=\frac{x+8}{5}$
Work Step by Step
$$f(x)=5x-8$$ $$y=5x-8$$ $$x=5y-8$$ $$5y=x+8$$ $$y=\frac{x+8}{5}$$ $$f^{-1}(x)=\frac{x+8}{5}$$
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