Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.4 - Inverse of a Function - Exercises - Page 574: 66

Answer

$8t^2+8t-1$

Work Step by Step

The given expression is $=(t^2-4t-4)+(7t^2+12t+3)$ Clear the parentheses. $=t^2-4t-4+7t^2+12t+3$ Group like terms. $=t^2+7t^2-4t+12t-4+3$ Combine like terms. $=8t^2+8t-1$
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