Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 565: 42

Answer

The solution is $x=-14$.

Work Step by Step

The given equation is $\Rightarrow -5=\sqrt[3]{10x+15}$ Cube each side of the equation. $\Rightarrow (-5)^3=(\sqrt[3]{10x+15})^3$ Simplify. $\Rightarrow -125=10x+15$ Subtract $15$ from each side. $\Rightarrow -125-15=10x+15-15$ Simplify. $\Rightarrow -140=10x$ Divide each side by $10$. $\Rightarrow -14=x$ Check $x=-14$. $\Rightarrow -5=\sqrt[3]{10x+15}$ $\Rightarrow -5=\sqrt[3]{10(-14)+15}$ $\Rightarrow -5=\sqrt[3]{-140+15}$ $\Rightarrow -5=\sqrt[3]{-125}$ $\Rightarrow -5=\sqrt[3]{(-5)^3}$ $\Rightarrow -5=-5$ True. Hence, the solution is $x=-14$.
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