Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.2 - Graphing Cube Root Functions - Exercises - Page 556: 46

Answer

The solution set is $\{-6,6\}$.

Work Step by Step

The given expression is $\Rightarrow x^2-36=0$ Add $36$ to each side. $\Rightarrow x^2-36+36=0+36$ Simplify. $\Rightarrow x^2=36$ $36\geq0$ is a nonnegative number. Use the square root method. $\Rightarrow x=\pm\sqrt {36}$ Use $\sqrt {36}=6$. $\Rightarrow x=\pm 6$ Hence, the solution set is $\{-6,6\}$.
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