Answer
The factor of the given polynomial is $(d-7)(d-4)$.
Work Step by Step
The given polynomial is
$=d^2-11d+28$
Rewrite $-11x$ as $-7d-4d$.
$=d^2-7d-4d+28$
Group the terms.
$=(d^2-7d)+(-4d+28)$
Factor each group.
$=d(d-7)-4(d-7)$
Factor out $(d-7)$.
$=(d-7)(d-4)$
Hence, the factor of the given polynomial is $(d-7)(d-4)$.
