Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 1 - Solving Linear Equations - Chapter Review - Page 46: 23

Answer

a. $K= \frac{5(F-32)}{9}+273.15$ b. $k\approx 355.37$

Work Step by Step

a. The given formula is $\Rightarrow F=\frac{9}{5}(K-273.15)+32$ Subtract $32$ from each side. $\Rightarrow F-32=\frac{9}{5}(K-273.15)+32-32$ Simplify. $\Rightarrow F-32=\frac{9}{5}(K-273.15)$ Multiply each side by $\frac{5}{9}$. $\Rightarrow \frac{5(F-32)}{9}=\frac{5}{9}\cdot \frac{9}{5}(K-273.15)$ Simplify. $\Rightarrow \frac{5(F-32)}{9}=K-273.15$ Add $273.15$ to each side. $\Rightarrow \frac{5(F-32)}{9}+273.15=K-273.15+273.15$ Simplify. $\Rightarrow \frac{5(F-32)}{9}+273.15=K$ b. Substitute $180$ for $F$ in the above equation. $\Rightarrow \frac{5(180-32)}{9}+273.15=K$ Subtract. $\Rightarrow \frac{5(148)}{9}+273.15=K$ Simplify. $\Rightarrow 82.22+273.15\approx K$ $\Rightarrow 355.37\approx K$
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