Answer
Outbound flight: $2.5$ hours
Return flight: $2.3$ hours
Work Step by Step
Let's call the time for the outbound flight $t$ (in hours) and the time for the return flight $4.8 - t$ since the total flying time is $4.8$ hours.
Now, let's use the formula:
$\text{Distance }= \text{Speed }\times\text{ Time}$
For the outbound flight:
Distance $= 460 \cdot t$
For the return flight:
Distance $= 500 \cdot (4.8 - t)$
Since the outbound and return flights cover the same distance (as they are the same flight in opposite directions), we can set these two expressions for distance equal to each other:
$460t = 500(4.8 - t)$
Now, let's solve for $t$:
$460t = 500 \cdot 4.8 - 500t$
Add $500t$ to both sides:
$460t + 500t = 500 \cdot 4.8$
Combine like terms:
$960t = 500 \cdot 4.8$
Now, divide both sides by $960$ to solve for $t$:
$t = \dfrac{500 \cdot 4.8}{ 960}$
$t = 2.5$ hours
So, the outbound flight takes $2.5$ hours.
Now, to find the return flight time:
Return flight time $= 4.8 - t = 4.8 - 2.5 = 2.3$ hours
