Answer
(a) $\frac{x}{3}\sqrt[3] 2$
(b) $2x\sqrt[5] {2x}$
Work Step by Step
(a) $\sqrt[3] {\frac{2x^3}{27}}=\sqrt[3] {\frac{2x^3}{3^3}}=\frac{x}{3}\sqrt[3] 2$
(b) $\sqrt[5] {64x^6}=\sqrt[5] {2^5(2)x^5x}=2x\sqrt[5] {2x}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 63: 46
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