Answer
(a) $-8z^3$
(b) $\frac{1}{y^2}$
Work Step by Step
(a) $(-2z)^3=(-2)^3.z^3=-8z^3$
(b) $\frac{(8y)^0}{y^2}=\frac{8^0.y^0}{y^2}=\frac{(1)(1)}{y^2}=\frac{1}{y^2}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - Review Exercises - Page 62: 33
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