Answer
All real numbers except $x=2$ and $x=-5$
Work Step by Step
$\frac{x^2-1}{x^2+3x-10}$
The denominator can not be equal to zero:
$x^2+3x-10\ne0$
$x^2+5x-2x-10\ne0$
$x(x+5)-2(x+5)\ne0$
$(x-2)(x+5)\ne0$
$x\ne2$ and $x\ne-5$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.5 - Rational Expressions - Exercises - Page 48: 12
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