Answer
$4\sqrt[3] 4$
Work Step by Step
$\frac{8}{\sqrt[3] 2}=\frac{8}{\sqrt[3] 2}\frac{\sqrt[3] {2^2}}{\sqrt[3] {2^2}}=\frac{8\sqrt[3] {2^2}}{\sqrt[3] {2^3}}=\frac{8\sqrt[3] {2^2}}{2}=4\sqrt[3] {2^2}=4\sqrt[3] 4$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 25: 52
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