Answer
a) $32y^2$
b) $\frac{1}{(z+2)^{4}}$
Work Step by Step
a) $(4y^{-2})(8y^4)=4\cdot8\cdot y^{-2+4}=32y^2$
b) $(z+2)^{-3}(z+2)^{-1}=(z+2)^{-3-1}=(z+2)^{-4}=\frac{1}{(z+2)^{4}}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 24: 28
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