Answer
$(\dfrac{4}{3},\dfrac{4}{3})$
Work Step by Step
Here, we have $6x-3y=4 \implies x=4-2y$
Now, plug $x=4-2y$ into the second equation.
$6(4-2y)-3y=4$
$ 24-12y-3y=4$
$15y=20 \implies y=\dfrac{4}{3}$
Use the $y$ value and the equation above to solve for $x$:
$ x=4-2(\dfrac{4}{3})=\dfrac{4}{3}$
Hence, $(x,y)=(\dfrac{4}{3},\dfrac{4}{3})$
