Answer
$u=\frac{\sqrt 2}{2}i+\frac{\sqrt 2}{2}j$
Work Step by Step
$||v||=\sqrt {v·v}=\sqrt {(i+j)·(i+j)}=\sqrt {1+1}=\sqrt 2$
$u=\frac{v}{||v||}=\frac{i+v}{\sqrt 2}=\frac{1}{\sqrt 2}i+\frac{1}{\sqrt 2}j=\frac{\sqrt 2}{2}i+\frac{\sqrt 2}{2}j$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 8 - Cumulative Test for Chapters 6-8 - Page 621: 34
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