Answer
$24~volts$
Work Step by Step
$Voltage=|E|$
$|a+bi|=\sqrt {a^2+b^2}$
$E=12\sqrt 3+12i$
$|E|=\sqrt {(12\sqrt 3)^2+12^2}=\sqrt {144(3)+144}=\sqrt {432+144}=\sqrt {576}=24$
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