Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Chapter 8 - 8.3 - Vectors in the Plane - 8.3 Exercises - Page 587: 91

Answer

$19.5^{\circ}$

Work Step by Step

The sine of an angle is defined as force over weight. Thus, $ \sin \theta=\dfrac{force}{weight}=\dfrac{5000}{15000}$ This implies that $ \theta=\sin^{-1} [\dfrac{5000}{15000}]$ or, $\theta =19.5^{\circ}$
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