Answer
$\theta = 60^{o}$
d = 31.22
c = 52.20
Work Step by Step
The following are the given values:
a = 25
b = 35
$\phi = 120^{o}$
Finding $\theta$:
A parallelogram has a total of $360^{o}$. Using that information:
120 + 120 = 240
360 - 240 = 120
$\frac{120}{2} = 60^{o}$
$\theta = 60^{o}$
Using the Law of Cosines, we can find d:
$d^{2} = 25^{2} + 35^{2} - 2(25)(35)cos(60^{o})$
d = 31.22
Using the Law of Cosines, we can find c:
$c^{2} = 25^{2} + 35^{2} - 2(25)(35)cos(120^{o})$
c = 52.20
$\theta = 60^{o}$
d = 31.22
c = 52.20
