Answer
$θ\approx23.847°$
Work Step by Step
$r=\frac{1}{32}v_0^2~sin~2θ$
$v_0=75~ft/s$ and $r=130~ft$
$130=\frac{1}{32}(75)^2~sin~2θ$
$130=\frac{5625}{32}~sin~2θ$
$\frac{130\times32}{5625}=sin~2θ$
$sin~2θ=0.7395555...$
$2θ=arcsin(0.7395555...)$
$θ=\frac{arcsin(0.7395555...)}{2}$
$θ\approx23.847°$