Answer
a) $\sqrt {2} \sin \theta+\dfrac{\pi}{4}$
b) $\sqrt {2} \cos \theta -\dfrac{\pi}{4}$
Work Step by Step
a) We need to plug data into the given equation.
$y=\sqrt {(1)^2+(1)^2} \sin \theta+\arctan (1)$
This implies that $y=\sqrt {2} \sin \theta+\dfrac{\pi}{4}$
b) We need to plug data into the given equation.
$y=\sqrt {(1)^2+(1)^2} \cos \theta -\arctan (1)$
This implies that $y=\sqrt {2} \cos \theta -\dfrac{\pi}{4}$
